Cold room insulation comparison

Compare up to three panel options by steady-state heat gain, the electricity your refrigeration system needs to remove it, energy cost and simple payback against option 1 — using your own quoted prices and datasheet values.

Project

Insulated surface area (m²)Average temperature difference (K)System COPSeasonal coefficient of performance of your refrigeration system.Electricity tariff (per kWh)

Option 1

Option 1 thickness (mm)Option 1 declared λ (W/m·K)From the supplier datasheet (aged value if declared).Option 1 price (per m²)Your quoted price — example only.

Option 2

Option 2 thickness (mm)Option 2 declared λ (W/m·K)From the supplier datasheet (aged value if declared).Option 2 price (per m²)Your quoted price — example only.

Option 3

Option 3 thickness (mm)Option 3 declared λ (W/m·K)From the supplier datasheet (aged value if declared).Option 3 price (per m²)Your quoted price — example only.

Option	mm	λ	Heat gain W	Electricity kWh/yr	Energy cost/yr	Capex	Payback vs option 1 (yr)
Option 1	100	0.022	3,960	17,345	2,602	enter price	—
Option 2	150	0.022	2,640	11,563	1,734	enter price	enter prices
Option 3	200	0.022	1,980	8,672	1,301	enter price	enter prices

Use in a team-reviewed RFQ Save to a free project (sign-in)

Formula and limits

Heat gain W = λ ÷ thickness × area × ΔT. Electricity kWh/yr = heat gain × 8,760 h ÷ 1000 ÷ COP. Payback = extra capex ÷ annual energy saving. Joints, thermal bridges, ageing, moisture and door frames reduce real performance; fire rating, food-contact finishes and structural span matter as much as λ.

First-pass planning estimate using steady-state formulas and the inputs you enter. It is not an engineering design, certification or supplier quotation; a qualified refrigeration engineer must confirm the design basis. Example inputs are placeholders, not benchmarks.

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